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antoniya [11.8K]

2 years ago

11

Use the square root method to find the solutions to the quadratic equation 22

1 answer:

lakkis [162]2 years ago

5 0

Answer:

$x = 2\sqrt{2}, -2\sqrt{2}$

Step-by-step explanation:

Given

$x^2 - 8 = 0$

Required

Solve

We have:

$x^2 - 8 = 0$

Add 8 to both sides

$x^2 = 8$

Take square roots of both sides

$x = \±\sqrt{8}$

Expand

$x = \±\sqrt{4*2}$

This gives:

$x = \±2\sqrt{2}$

Split

$x = 2\sqrt{2}, -2\sqrt{2}$

You might be interested in

What does it mean to find the value of a numerical or algebraic expression?

Alenkinab [10]

Answer:

Evaluate. To find the value of a numerical or algebraic expression. Variable. a symbol (like x or y) that is used in mathematical or logical expressions to represent a variable quantity.

Step-by-step explanation:

Hope this help!!

3 0

2 years ago

6n+n+14=0 i need the math

Fofino [41]

Let's solve your equation step-by-step.<span><span><span><span>6n</span>+n</span>+14</span>=0</span>

Step 1: Simplify both sides of the equation.<span><span><span><span>6n</span>+n</span>+14</span>=0</span><span>Simplify: (Show steps)</span><span><span><span>7n</span>+14</span>=0</span>

Step 2: Subtract 14 from both sides.<span><span><span><span>7n</span>+14</span>−14</span>=<span>0−14</span></span><span><span>7n</span>=<span>−14</span></span>

Step 3: Divide both sides by 7.<span><span><span>7n</span>7</span>=<span><span>−14</span>7</span></span><span>n=<span>−2</span></span>

Answer:<span>n=<span>−<span>2</span></span></span>

6 0

3 years ago

The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of

ycow [4]

The length of the longer base is 41 ft.

<u><em>Explanation</em></u>

Lets assume, length of one base is $x$ ft.

As, another base is 19 less than five times the length of this base, so the length of another base $= (5x- 19) ft.$

The trapezoid has a height of 18 ft and area of 477 ft²

Formula for Area of trapezoid, $A=\frac{1}{2} (a+b)*h$ , where $a, b$ = Two bases of trapezoid and $h$ = height of the trapezoid.

Given in the question: $A= 477$ and $h= 18$

We have also two bases as: $a= x$ and $b= 5x-19$

So, according to the above formula...

$A= \frac{1}{2}(a+b)h\\\\ 477=\frac{1}{2}(x+5x-19)*18\\\\ 477=9(6x-19)\\\\477= 54x-171\\\\477+171=54x\\\\648=54x\\\\x=\frac{648}{54} = 12$

So, length of one base is $12 ft$ and another base $=(5*12-19)ft =(60-19)ft = 41 ft$

That means, the length of the longer base is 41 ft.

8 0

2 years ago

Ally is making a scale diagram of her classroom. She uses a scale factor of 3 centimeters per foot to draw the diagram. The actu

frozen [14]

Multiply 18 * 3 and 20 * 3

18*3 = 54

20 * 3 = 60

Length = 54 cm ; Width = 60 cm

Area = L x W

54 * 60 = 3240

Area = 3240 cm

6 0

3 years ago

PLS SHOW UR SOLUTIONS

maksim [4K]

Answer:

Q1. $(2x-3)^{2}+3(x-4)=5+y\\$

$4x^{2} -12x+9+3x-12-5-y=0$

$4x^{2} -9x-8-y=0$

$4x^{2} -9x-8=y$

∴ $y = 4x^{2} -9x-8$

∴ From the quadratic equation above, a = 4, b = -9, and c = -8.

Q2. $(x-5)^{2} -x^{2} =y$

$x^{2} -10x+25-x^{2} =y$

$-10x+25=y$

∴ $y = -10x + 25$

∴ The equation above is not a quadratic equation as it does not follow the format of ax² + bx + c.

Q3. $2x(4x^{2} -4x+1)=y+x(8x)+4(2x)$

$8x^{3} -8x^{2} +2x-8x^{2} -8x=y$

∴ $y=8x^{3} -16x^{2} -6x$

∴ The equation above is not a quadratic equation as it does not follow the format of y = ax² + bx + c.

8 0

11 months ago