Answer: The domain of f(x) is all real numbers,
and range of f(x) is
.
Explanation:
The given function is,
![f(x)=(\frac{1}{6})^x+2](https://tex.z-dn.net/?f=f%28x%29%3D%28%5Cfrac%7B1%7D%7B6%7D%29%5Ex%2B2)
The domain is the set of all possible values for which the value of function exist.
The given function is defined for any real value of x, therefore the domain of the function is set of all real number. it can be written in interval notation
.
The range is the set of possible value of f(x) at different value of x. Range is the set of outputs.
In the given function,
![(\frac{1}{6})^x>0](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B6%7D%29%5Ex%3E0)
for any value of x.
So,
![(\frac{1}{6})^x+2>0+2](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B6%7D%29%5Ex%2B2%3E0%2B2)
![f(x)>2](https://tex.z-dn.net/?f=f%28x%29%3E2)
Therefore the value of f(x) is always greater than 2 and the range of the function is
.
Answer: 1/2a-4b
Step-by-step explanation:
When combining like terms you can only combine numbers with the same variables.
So we subtract 3/4a-1/4a=1/2a
And then we subtract the b values
2b-6b=-4b
1/2a-4b
1. AD and BC bisects each other at E
1. Given
2. ABE ≈DCE
2. Vertical Angles
3. ABE≈DCE
3. SAS postulate
Answer:
10 km
Step-by-step explanation:
Running distance = 8 km
Sprinting distance = 0.5
Climbing distance = <u> 1.5 </u>
TOTAL = 10 km
Jamal travelled 10 km in total.