Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
Answer:
x ≈ 11.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sin∅ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle = 35°
Opposite Leg = <em>x</em>
Hypotenuse = 20
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [sine]: sin35° = x/20
- Isolate <em>x</em>: 20sin35° = x
- Evaluate: 11.4715 = x
- Rewrite: x = 11.4715
- Round: x ≈ 11.5
i think is acute angle because acute angle are angles that are more than zero but less than 90
Answer with Step-by-step explanation:
We are given S be any set which is countable and nonempty.
We have to prove that their exist a surjection g:N
Surjection: It is also called onto function .When cardinality of domain set is greater than or equal to cardinality of range set then the function is onto
Cardinality of natural numbers set =
( Aleph naught)
There are two cases
1.S is finite nonempty set
2.S is countably infinite set
1.When S is finite set and nonempty set
Then cardinality of set S is any constant number which is less than the cardinality of set of natura number
Therefore, their exist a surjection from N to S.
2.When S is countably infinite set and cardinality with aleph naught
Then cardinality of set S is equal to cardinality of set of natural .Therefore, their exist a surjection from N to S.
Hence, proved
4+4+3+3 because if you look to each corner there is 4 and on the other corner there is 3 and 3