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nlexa [21]
2 years ago
13

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
1 answer:
Bond [772]2 years ago
3 0

Answer:

it is the reflection in the x-axis

Step-by-step explanation:

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write the equation in standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0).
Mashcka [7]

Standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0) is \frac{x^{2} }{144}-\frac{y^{2} }{25}=1

Hyperbola is a plane curve generated by a point so moving that the difference of the distances from two fixed points is a constant.

Given,

The Vertices of the hyperbola =  (-12,0) and (12,0)

Foci = (-13,0) and (13,0)

a=12

ac=13

c=\frac{13}{12}

We know,

c=\sqrt{1+\frac{b^{2} }{a^{2} } }

c^{2}=1+\frac{b^{2} }{a^{2} }  \\(\frac{13}{12} )^{2}=1+\frac{b^{2} }{144}  \\\frac{169}{144}=1+ \frac{b^{2} }{144} \\\frac{b^{2} }{144} =\frac{25}{144}\\ b^{2}=25

The equation of the hyperbola is

\frac{x^{2} }{a^{2} }-\frac{y^{2} }{b^{2} }=1\\  \frac{x^{2} }{144 }-\frac{y^{2} }{25 }=1

Hence, the standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0) is \frac{x^{2} }{144}-\frac{y^{2} }{25}=1

Learn more about hyperbola here

brainly.com/question/7098764

#SPJ4

4 0
1 year ago
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