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nlexa [21]
2 years ago
13

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
1 answer:
Bond [772]2 years ago
3 0

Answer:

it is the reflection in the x-axis

Step-by-step explanation:

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Why does the graph of a proportional relationship must pass through the origin (0,0)
ELEN [110]

Answer:

Directly proportional relationships always pass through the origin (0,0). There are other linear relationships that do not pass through the origin.

4 0
3 years ago
Factor completely.<br> ​ <br> 18b−32<br> ​<br> Enter your answer in the boxes.<br><br> ___(___)
Kamila [148]
To factor completely 18b - 32, we factor out the common factor of the two terms and divide each of term by the common factor.

18b - 32 = 2(18b/2 - 32/2) = 2(9b - 16)
5 0
3 years ago
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Which two values of x are roots of the polynomial below?<br> x2-11x + 15
Alex787 [66]

The two values of roots of the polynomial x^{2}-11 x+15 are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

<u>Solution:</u>

Given, polynomial expression is x^{2}-11 x+15

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Given that x^{2}-11 x+15

Here a = 1, b = -11 and c = 15

On substituting the values we get,

x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}

\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}

Hence, the roots of given polynomial are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

6 0
3 years ago
Look at the black points on the graph. Fill in the
Ira Lisetskai [31]

Answer:

(0,1) and (5,32)

Step-by-step explanation:

Edg.2020

6 0
3 years ago
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What value of g makes the equation true?
Ipatiy [6.2K]
(x+7)(x-4)
= x^2 + 7x - 4x - 28
= x^2 + 3x - 28

answer
g = 3
4 0
2 years ago
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