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konstantin123 [22]
3 years ago
7

120 is the product of 8 and Julie's score.

Mathematics
1 answer:
adell [148]3 years ago
5 0

Answer:

Julie's score is 15.

Step-by-step explanation:

This can be solved in two ways:

⇒ 120 ÷ 8

⇒ Experimentation on what × 8 = 120 (adding random numbers until you get 120 as a product).

Let's use the first method.

⇒ 120 ÷ 8

         1 5

   __________

8 |  1  2 0

   -     8

        ____

        4    0

       - 4  0

      ____

       0

Therefore, Julie's score is 15.

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What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7
cestrela7 [59]

Answer:

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

Step-by-step explanation:

We need to find the solution for x in the given equation.

\sqrt{9x+7} +\sqrt{2x}=7

Solving:

Subtract \sqrt{2x} from both sides

\sqrt{9x+7} =7-\sqrt{2x}

Taking square on both sides

(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation  \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764

Putting values and solving

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Verifying the solution by putting values of x in given equation

Putting x=18

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(18)+7} +\sqrt{2(18)}=7\\\sqrt{169} +\sqrt{36}=7\\13+6=7\\19\neq 7

So, x=18 is not solution o given equation.

Putting x = 2

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(2)+7} +\sqrt{2(2)}=7\\\sqrt{25} +\sqrt{4}=7\\5+2=7\\7=7

So, x=2 satisfies the equation

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

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Answer:

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