B) 14.
If you start with subtracting the 8 pages from 50, you get 42 remaining pages. Then it says 2/3 of the REMAINING pages so you divide 42 into thirds. 42/3=14. You want 2/3 of that, so you multiply the 14 by two to get 28 (it's like there are three piles of 14 pages and you want only 2 out of the three piles). So now you've used 28 pages + the original 8. You've used a TOTAL of 36 pages. Subtract 36 from 50 and you get 14 left.
<span>12.3
Volume function: v(x) = ((18-x)(x-1)^2)/(4pi)
Since the perimeter of the piece of sheet metal is 36, the height of the tube created will be 36/2 - x = 18-x.
The volume of the tube will be the area of the cross section multiplied by the height. The area of the cross section will be pi r^2 and r will be (x-1)/(2pi). So the volume of the tube is
v(x) = (18-x)pi((x-1)/(2pi))^2
v(x) = (18-x)pi((x-1)^2/(4pi^2))
v(x) = ((18-x)(x-1)^2)/(4pi)
The maximum volume will happen when the value of the first derivative is zero. So calculate the first derivative:
v'(x) = (x-1)(3x - 37) / (4pi)
Convert to quadratic equation.
(3x^2 - 40x + 37)/(4pi) = 0
3/(4pi)x^2 - (10/pi)x + 37/(4pi) = 0
Now calculate the roots using the quadratic formula with a = 3/(4pi), b = -10/pi, and c = 37/(4pi)
The roots occur at x = 1 and x = 12 1/3. There are the points where the slope of the volume equation is zero. The root of 1 happens just as the volume of the tube is 0. So the root of 12 1/3 is the value you want where the volume of the tube is maximized. So the answer to the nearest tenth is 12.3</span>
Answer:
x = -9, y = 6.
Step-by-step explanation:
-x + y = 15
-5x - 3y = 27
From the first equation:
y = x + 15.
Substituting for y in second equation:
-5x - 3(x + 15) = 27
-8x - 45 = 27
-8x = 72
x = -9.
Now plug x = -9 into equation 1
-(-9) + y = 15
y = 15 -9 = 6.
just to clarify the engineering notation, E6 is just 1 and 6 zeros, or a million, thus, 107,000,000 is just 107E6.
Answer:
Step-by-step explanation:
a) 3 x 5
b) 15 Celcius
