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iragen [17]
2 years ago
7

I need help answering this question!

Mathematics
1 answer:
Molodets [167]2 years ago
8 0

Answer:

2x+7=-3+2x multiply what’s in the bracket by the negative sign

Collect like terms

2x-2x=-3-7, so

0=-10

Step-by-step explanation:

I hope this is the answer, if it helped please give me brainliest

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What is the circumference of a circle whose radius is 13?
Inessa05 [86]

Answer:

Circumference, C = 81.68 units

Step-by-step explanation:

Given that,

The radius of the circle, r = 13 units

We need to find the circumference of the circle. The circumference of a circle is the sum of the outer boundary. For a circle, it is given by :

C=2\ \pi r

C=2\ \pi \times 13

C = 81.68 units

So, the circumference of the circle is 81.68 units. Hence, this is the required solution.

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Step-by-step explanation:

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Given that f ( x ) = 8 x + 5 f ( x ) = 8 x + 5 and g ( x ) = 3 − x 2 g ( x ) = 3 - x 2 , calculate f(g(0))
Alex17521 [72]

Answer:

29

Step-by-step explanation:

g(0)=3-2(0)

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5 0
2 years ago
What is 1/5 divided by 1 2/5
rodikova [14]

Answer:

1/7

Step-by-step explanation:

so 1/5 divided by 7/5 is 1/5 times 5/7, which is 1/7

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Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2
NNADVOKAT [17]

y'-\dfrac13y=\dfrac13xe^x\ln x\,y^{-2}

Divide both sides by \dfrac13y^{-2}(x):

3y^2y'-y^3=xe^x\ln x

Substitute v(x)=y(x)^3, so that v'(x)=3y(x)^2y'(x).

v'-v=xe^x\ln x

Multiply both sides by e^{-x}:

e^{-x}v'-e^{-x}v=x\ln x

The left side can be condensed into the derivative of a product.

(e^{-x}v)'=x\ln x

Integrate both sides to get

e^{-x}v=\dfrac12x^2\ln x-\dfrac14x^2+C

Solve for v(x):

v=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x

Solve for y(x):

y^3=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x

\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}

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