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aliya0001 [1]
2 years ago
8

Can someone please help me answer this question please

Mathematics
1 answer:
Alinara [238K]2 years ago
8 0

Answer:

1.791875241 ^{13}

This is answer

like

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The average attendance at school for 5 days was 264. If the attendance on the 5th day was 256, calculate the average attendance
Tema [17]

Answer:

266

Step-by-step explanation:

Let the attendence of 5days be a,b,c,d,e

given,

(a+b+c+d+e)/5=264

a+b+c+d+256=264*5 [since 5th day=256]

(a+b+c+d+)/4=1(320-256)/4 [dividing both side by 4]

average attendence of 4 days =266

5 0
3 years ago
In ΔNOP, m ∠ N = ( 9 x + 8 ) ∘ m∠N=(9x+8) ∘ , m ∠ O = ( 4 x + 13 ) ∘ m∠O=(4x+13) ∘ , and m ∠ P = ( 2 x − 6 ) ∘ m∠P=(2x−6) ∘ . Fi
Mashutka [201]

Answer: -0=

Step-by-step explanation:

3 0
3 years ago
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m
Marta_Voda [28]

Answer:

\bar X = \frac{2276}{48}=47.417

If we compare this value with the 47.3 proposed we have the following error

Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%

The computed mean is close to the actual mean because the difference between the means is less than 5%.  

Step-by-step explanation:

Assuming the following dataset:

Speed   42-45  46-49  50-53  54-57  58-61

Freq.         21        15        6           4          2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}

And is useful construct a table like this one:

Speed     Freq    Midpoint   Freq*Midpoint

42-45       21            43.5       913.5

46-49       15            47.5        712.5

50-53       6             51.5         309

54-57        4            55.5         222

58-61        2             59.5        119

Total       48                           2276

And the mean is given by:

\bar X = \frac{2276}{48}=47.417

If we compare this value with the 47.3 proposed we have the following error

Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%

The computed mean is close to the actual mean because the difference between the means is less than 5%.  

6 0
3 years ago
The limit as x-approaches 3 of f(x) is x-3 over x squared -9
Luden [163]

notice that the denominator can be factored into (x-3)(x+3).

Now you can cross out (x - 3) from the numerator and denomiantor resulting in a simplified fraction of \frac{1}{x+3}

Plug the limit value (which is 3) into the simplified fraction.

Answer: \frac{1}{6}

4 0
3 years ago
Part A
rjkz [21]

Answer:

Step-by-step explanation:

Part A

Solve 4,500 ÷ 90. Enter your answer in the box.

 

Answer : 50

Part B

Select all the expressions that are equal to 4,500 ÷ 90.

A. 4,500 ÷ 9 tens  ✔️

B. 450 ÷ 90  ❌

C. 450 ÷ 9  ❌

D. 4,500 ÷ 9  ❌

E. 4,500 ÷ 90 tens ❌

8 0
3 years ago
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