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aliya0001 [1]
2 years ago
8

Can someone please help me answer this question please

Mathematics
1 answer:
Alinara [238K]2 years ago
8 0

Answer:

1.791875241 ^{13}

This is answer

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What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
3 years ago
Find the volume of the solid obtained by rotating the region bounded by y=4x and y=2sqrt(x) about the line x=6.
Pie

Check the picture below.

so by graphing those two, we get that little section in gray as you see there, now, x = 6  is a vertical line, so we'll have to put the equations in y-terms and this is a washer, so we'll use the washer method.

y=4x\implies \cfrac{y}{4}=x\qquad \qquad y=2\sqrt{x}\implies \cfrac{y^2}{4}=x~\hfill \begin{cases} \cfrac{y}{4}=x\\\\ \cfrac{y^2}{4}=x \end{cases}

the way I get the radii is by using the "area under the curve" way, namely, I use it to get R² once and again to get r² and using each time the axis of rotation as one of my functions, in this case the axis of rotation will be f(x), and to get R² will use the "farthest from the axis of rotation" radius, and for r² the "closest to the axis of rotation".

\stackrel{R}{\stackrel{f(x)}{6}-\stackrel{g(x)}{\cfrac{y^2}{4}}}\qquad \qquad \stackrel{r}{\stackrel{f(x)}{6}-\stackrel{g(x)}{\cfrac{y}{4}}}~\hfill \stackrel{R^2}{\left( 6-\cfrac{y^2}{4} \right)^2}-\stackrel{r^2}{\left( 6-\cfrac{y}{4} \right)^2} \\\\\\ \stackrel{\textit{doing a binomial expansion and simplification}}{3y-3y^2-\cfrac{y^2}{16}+\cfrac{y^4}{16}}

now, both lines if do an equation on where they meet or where one equals the other, we'd get the values for y = 0 and y = 1, not surprisingly in the picture.

\displaystyle\pi \int_0^1\left( 3y-3y^2-\cfrac{y^2}{16}+\cfrac{y^4}{16} \right)dy\implies \pi \left( \left. \cfrac{3y^2}{2} \right]_0^1-\left. y^3\cfrac{}{} \right]_0^1-\left. \cfrac{y^3}{48}\right]_0^1+\left. \cfrac{y^5}{80} \right]_0^1 \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{59\pi }{120}~\hfill

7 0
2 years ago
Roy has a bag containing green, blue, red, brown, and black marbles. He randomly picks a marble and replaces it. He repeats this
Novosadov [1.4K]

Answer:

Green: 0.3

Blue: 0.1

Red: 0.35

Brown: 0.15

Black: 0.1

cannot

Step-by-step explanation:

Hi, thank you for posting your question here in Brainly.

To find the probability of an event, you have to divide the number of trials of that event that succeeded to the total number of trials. Based on that definition, the probability would be 18/60=0.3, 6/60=0.1, 21/60=0.35, 9/60=0.15, 6/60=0.1

I hope i helped you out and helped you learn something new :)

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Prime factorization?
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Can  someone please help me answer this problem  
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61.3% equals 0.00613, 61.3, 6.13, 0.613, 0.0613
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You move the decimal point two places to the left when converting percentages to decimals. 

0.613
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3 years ago
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