Answer:
266
Step-by-step explanation:
Let the attendence of 5days be a,b,c,d,e
given,
(a+b+c+d+e)/5=264
a+b+c+d+256=264*5 [since 5th day=256]
(a+b+c+d+)/4=1(320-256)/4 [dividing both side by 4]
average attendence of 4 days =266
Answer:

If we compare this value with the 47.3 proposed we have the following error

The computed mean is close to the actual mean because the difference between the means is less than 5%.
Step-by-step explanation:
Assuming the following dataset:
Speed 42-45 46-49 50-53 54-57 58-61
Freq. 21 15 6 4 2
And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

And is useful construct a table like this one:
Speed Freq Midpoint Freq*Midpoint
42-45 21 43.5 913.5
46-49 15 47.5 712.5
50-53 6 51.5 309
54-57 4 55.5 222
58-61 2 59.5 119
Total 48 2276
And the mean is given by:

If we compare this value with the 47.3 proposed we have the following error

The computed mean is close to the actual mean because the difference between the means is less than 5%.
notice that the denominator can be factored into (x-3)(x+3).
Now you can cross out (x - 3) from the numerator and denomiantor resulting in a simplified fraction of 
Plug the limit value (which is 3) into the simplified fraction.
Answer: 
Answer:
Step-by-step explanation:
Part A
Solve 4,500 ÷ 90. Enter your answer in the box.
Answer : 50
Part B
Select all the expressions that are equal to 4,500 ÷ 90.
A. 4,500 ÷ 9 tens ✔️
B. 450 ÷ 90 ❌
C. 450 ÷ 9 ❌
D. 4,500 ÷ 9 ❌
E. 4,500 ÷ 90 tens ❌