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1 year ago

What is the midpoint of AB?

Mathematics

2 answers:

spayn [35]1 year ago

6 0

Answer: Point G.

Step-by-step explanation:

Count the number of spaces between points A and B. Then divide that number by 2 and count that many spaces from one point.

14/2=7

I hope this helps!! Pls mark brainliest :)

Viefleur [7K]1 year ago

3 0

Point G is the answer, literally look at it, anyways trust

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Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

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Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

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Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After

Katena32 [7]

<span>Find the speed of each car.
Let a be the first car
Let b be the second car
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=> b = x + 12 miles per hour
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=> 2x + 12 = 232
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