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2 years ago

Profitability, consumer relations, and competition are involved in what kinds of concerns in the design process?

Computers and Technology

1 answer:

gogolik [260]2 years ago

5 0

Profitability, consumer relations, and competition are involved in Product Development and Commercialization.

<h3>What are the stages of product development?</h3>

The stages of the New Product Development act are:

Idea Generation.
Screening.
Concept Development.
Product Development and Commercialization.

Note that Product development and commercialization is known to be the supply line management method that helps to give structure for creating and bringing in of new products in line with customers and suppliers in the market.

Therefore, one can say that Profitability, consumer relations, and competition are involved in Product Development and Commercialization.

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You are an IT administrator troubleshooting a Windows-based computer. After a while, you determine that you need to refresh the

Tanya [424]

Answer:

gpupdate

Explanation:

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2 years ago

write a program that computes an integer's checksum. to compute the checksum, break the integer into its constituent

Serggg [28]

Using the knowledge in computational language in python it is possible to write a code that computes an integer's checksum.

<h3>Writting the code:</h3>

def checkSum(n): # Function definition

total = 0 # total variable which returns sum

c = 0 # counter variable which count the even position

while(n!=0): # running a loop while n != 0

r = int(n%10) #breaking the number into digits

c=c+1 # increase counter

if c%2==0: # if counter is even position then double the number

r = r*2

while(r!=0): # do the process

total = total + int(r%10)

r = int(r/10)

n=int(n/10)

else: # if counter is odd position then simple add the digit

total = total + r # into total

n=int(n/10)

return total # in the last return the sum of digits

# Driver code

n = int(input("Enter Number:")) # asking user to enter the number

print(checkSum(n)) # calling the function

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8 0

1 year ago

Which guideline should you follow when selecting the font for a presentation

Sladkaya [172]

My school requires us to use Arial and double space it but we have to use font size 30 for title and 24 for the paragraphs.

3 0

3 years ago

Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,

nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
P5 will not be allocated to any of the available space because none can contain it.
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

8 0

3 years ago

Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)

Mnenie [13.5K]

Answer:

(1)Minterms complement = XYZ (2) Compliment of Minterms = Σm(0,1, 2 , 4 , 6) (3) (X+Y+Z) (4) Minimized SOP = Z + XY

Manterms = πM

Explanation:

Solution

Recall that:

Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)

(1) Canonical Disjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as minterms

In Minterm we assign 'I' to each uncomplimented variable and '0' to each complemented/complementary variable

For the given question stated we ave the following:

Minterms = XYZ, XYZ, XYZ, XYZ, XYZ.

(2) Canonical Conjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as maxterms.

In Maxterms we assign '0' to each uncomplimented variable and '1' to each complemented/complementary variable

Compliment of Minterms = Σm(0,1, 2 , 4 , 6)

Maxterms = πM

Note: Kindly find an attached copy of the complete solution to this question below.

6 0

2 years ago