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Stolb23 [73]
2 years ago
10

What is the square root of x divided by the square root of 2 equal

Mathematics
1 answer:
ikadub [295]2 years ago
5 0

Answer:

\sqrt{\frac{x}{2} }

Key:

• \frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}

Step-by-step explanation:

\frac{\sqrt{x}}{\sqrt{2}}\\

\frac{\sqrt{x}}{\sqrt{2}}=\sqrt{\frac{x}{2}}\\

=\sqrt{\frac{x}{2}}

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What is the difference between the least common and the most common pet lengths? A line plot with the title Pet Measurements and
Alexxx [7]

Answer:

Step-by-step explanation:

In the line plot, the red dots above each measurement on the number line indicates the frequency of that particular measurement.

From the information given,

Measurement Frequency

fifteen inches 4

Twenty five inches 7

Thirty five inches 3

Fourty five inches 5

Fifty five inches 1

Therefore, the most common pet length is Twenty five inches.

The least common pet length is Fifty five inches.

The difference between the least common and the most common pet lengths is 7 - 1 = 6

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4 years ago
Bob and Sally mortgage payment increases to $1632.00. Their roof starts to leak and they need to replace it. They budget 500$ pe
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Answer:

...

Step-by-step explanation:

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3 years ago
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3 years ago
Wei is standing in wavy water and notices the depth of
dexar [7]

Answer:

  see the attachment

Step-by-step explanation:

The function can be ...

  D(t) = A +Bcos(C(t-p))

where A is the average depth (55+12)/2 = 33.5 cm,

  B is the peak deviation from average, 55 -33.5 = 21.5 cm,

  C is the horizontal scale factor (2π/T) = (2π/3) for a period (T) of 3 seconds,

and p is the phase offset, given as 1.1 seconds.

The function is ...

  D(t) = 33.5 +21.5cos(2π/3·(t -1.1))

5 0
3 years ago
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To find the standard equation for a circle centered at the origin, we use the distance formula, since the radius measures? A. Th
masya89 [10]

Answer:

  A. The distance from any point in the circle to the origin

Step-by-step explanation:

The distance formula tells you that the distance (d) is related to the coordinates of two points (x1, y1) and (x2, y2) by ...

  d² = (x2 -x1)² +(y2 -y1)²

For points (x, y) on the circle and (0, 0) at the origin, this becomes ...

  d² = (x -0)² +(y -0)²

If we want the distance to the point (x, y) to be equal to the radius of the circle, this becomes ...

  x² +y² = r² . . . . . . the standard equation of a circle centered at the origin

3 0
3 years ago
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