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AlexFokin [52]
1 year ago
11

Set of data with 350,000 numbers is normally

Mathematics
1 answer:
Rudiy271 year ago
7 0

Step-by-step explanation:

given a normal distribution with the given parameters the probability (= the % of the area of the distribution curve) for a number to be between 203 and 1803 is

0.9987

so, 99.87% of all numbers are expected to be in that range.

for 350,000 numbers that means

350,000×0.9987 = 349,545 numbers are expected to be between 203 and 1803.

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D = 18 in. Fine the radius or diameter of each circle with the given dimensions. ​
Alborosie

Answer:

r= 9

Step-by-step explanation:

radius (r) = diameter (D)/2

= 18/2

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4 0
3 years ago
A rectangular field has dimension of 91 feet by 60 and 1/3 feet what is the area of the field
Oliga [24]

Answer:

Area = 91*\frac{181}{3}=5490\frac{1}{3} square feet

Step-by-step explanation:

The area of a rectangle is given by the formula:

A = length * width

Where length is 91 feet and width is 60\frac{1}{3}  feet

Before we do the multiplication, we have to change the mixed number [width] into an improper fraction by using the rule shown below:

a\frac{b}{c}=\frac{(a*c)+b}{c}

Hence,

60\frac{1}{3}=\frac{181}{3}

So, the area is:

Area = 91*\frac{181}{3}=5490\frac{1}{3} square feet

8 0
3 years ago
What is the square root of 8 and 9? Can you show some work plz and thank you!
atroni [7]

Step-by-step explanation:

Square root means that the number that if you divide it. The number that if you divide it. The number you get multiply it self, will give you the answer. 8 doesn't have a square root, because 2×2= 4,4×4= 16.so 8 doesn't have a square root. But 9 has. 1×1= 1,2×2= 4,3×3= 9.Square root of 9 is 3

7 0
3 years ago
Read 2 more answers
Statistics grades: In a statistics class ofstudents, there weremen andwomen. Four of the men and five of the women received an A
Tomtit [17]

Answer:

(a) The probability that the student is a woman is \frac{n_{2}}{N}.

(b) The probability that a randomly selected student received an <em>A</em> is \frac{9}{N}.

(c) The probability that a student selected is a woman or received an <em>A</em> is \frac{n_{2}+4}{N}.

(d) The probability that a students selected did not receive an <em>A</em> is \frac{N-9}{N}.

Step-by-step explanation:

Let's assume that there were <em>N</em> students in a class.

Also assume that there are <em>n</em>₁ men and<em> </em><em>n</em>₂ women in the class.

Let's denote M = a student is a man, W = a student is a woman and A = a student received an <em>A</em> in the course.

It is provided that 4 men and 5 women received an <em>A</em> in the course.

The probability that a student is a man and he received an A is,

P(M\cap A)=\frac{4}{N}

The probability that a student is a woman and she received an A is,

P(W\cap A)=\frac{5}{N}

(a)

There are <em>n₂</em> students in the class who are female.

The probability that the student is a woman is,

P(W)=\frac{Number\ of\ women}{Total\ number\ of\ students}=\frac{n_{2}}{N}

(b)

The total number of students who received an <em>A</em> is, 9.

The probability that a randomly selected student received an <em>A</em> is:

P(A)=\frac{Number\ of\ student\ receiving\ an\ A}{Total\ number\ of\ students}=\frac{9}{N}

(c)

The probability that a student selected is a woman or received an <em>A</em> is:

P (W ∪ A) = P (W) + P(A) - P(W ∩ A)

                =\frac{n_{2}}{N}+\frac{9}{N}-\frac{5}{N} \\= \frac{n_{2}+9-5}{N}\\ = \frac{n_{2}+4}{N}

(d)

The probability that a students selected did not receive an <em>A</em> is:

P(A^{c})=1-P(A)\\=1 - \frac{9}{N}\\=\frac{N-9}{N}

8 0
3 years ago
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