2 years ago

25 POINTS HELP :( (giving brainliest)

1 answer:

3 0

Answer:

i don't know if you are right broooo ok thanks for your help and importance of urgency and Mick also download the matter of urgency of having a lot to be in a lot to be my last year but the best of luck for sound of urgency

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The soccer team collector $800 at a carwash fundraiser they charge five dollars for small vehicles and $10 for large vehicles th

Nadusha1986 [10]

800 - 50 = 750
750 ÷ 5 =150
150 small vehicles were washed

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2 years ago

The base of a triangle measures (3x − 6) units and the height measures (2x + 4) units.

ella [17]

Answer With Step-by-step explanation:

Part A:

.5[ (3x – 6) (2x + 4) ]

.5(6x^2 - 24)

3x^2 - 12

Part B:

Second Degree Binomial

Part C:

For Part A, a polynomial was multiplied by another polynomial. The resulting product was a polynomial. This is a demonstration of the closure property for multiplying polynomials.

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3 years ago

There are 25 counters in a bag: 6 red, 4 white, 7 blue, and 8 yellow. You choose one counter at random. Which color are you leas

Eduardwww [97]

You are least likely to choose white. Bc there are only 4 of those.

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2 years ago

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A particle moves so that r(t) = ati + b sin atj. Show that the magnitude of the acceleration of the particle is proportional to

ValentinkaMS [17]

Answer:

Step-by-step explanation:

Given

Position of particle is $r(t)=at\hat{i}+b\sin (at)\hat{j}$

i.e. distance from x axis is $b\sin (at)---1$

Distance from y axis at

velocity is given by $v=\frac{\mathrm{d} r}{\mathrm{d} t}$

$v=a\hat{i}+ba\cos (at)\hat{j}$

Similarly acceleration is given by

$a=\frac{\mathrm{d} v}{\mathrm{d} t}$

$a=0\hat{i}-a^2b\sin (at)\hat{j}$

Magnitude of acceleration is $=\sqrt{(-a^2b\sin (at))^2}$

$=a^2b\sin (at)----2$

From 1 and 2 we can see that

Magnitude of acceleration is proportional to distance from x axis

$a\propto distance\ from\ x-axis$

5 0

3 years ago

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The average annual income, I, in dollars, of a lawyer with an age of x years is modeled with the following function: I=-425x²+45

olchik [2.2K]

DI/dx=-850x+45500

d2l/d2x=-850 so when dl/dx=0 it is an absolute maximum for l(x)...

dl/dx=0 only when:

850x=45500

x=53.53

x=54 years of age (rounded)

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3 years ago

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