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Nata [24]
3 years ago
5

HELP I GOTTA PASS CLASS

Mathematics
2 answers:
Ymorist [56]3 years ago
7 0
The second answer , because m is the slope which is up 3 over two and the y intercept = 3 since the line crosses @3 on the y line
jek_recluse [69]3 years ago
4 0
The answer should be I think b
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Generate a frequency table for the following data: 3, 12, 25, 2, 3, 6, 17, 17, 15, 13, 20, 12, 21, 18, 19.
Cerrena [4.2K]

Answer:

5.

Step-by-step explanation:

There are 5 numbers in the data you have listed that are in between the numbers 15-20.

4 0
2 years ago
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A cafeteria manager needs to know how many apples and bananas to to order. He asked students to choose either an apple or a bana
Usimov [2.4K]

Answer:

Step-by-step explanation:

3/4 of total = 45

therefore, 1/4 took bananas

the ones taking bananas are 3 times less than those who took apples.

so we get 45/3 = 15 people picking bananas

7 0
3 years ago
2) Use the rules of exponents to evaluate or simplify. Write without negative exponents. 1 / 4^-2 = ____
lions [1.4K]
\frac{1}{4^{-2}}=\frac{1}{\left(\frac{1}{4}\right)^2}=\frac{1}{\frac{1}{4^2}}=4^2=16
5 0
3 years ago
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Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.
galben [10]

Answer:

The interval of increase of g(x) is (-6,+\infty).

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be g(x) = 190 + 8 \cdot x^{3} + x^{4}, the first derivative of the function is:

g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}

g'(x) = 4 \cdot x^{2}\cdot (6+x)

The following condition must be met to define the interval of increase:

4\cdot x^{2} \cdot (x+6) > 0

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

x + 6 > 0

The solution to this inequation is:

x > - 6

Now, the solution to this expression in interval notation is: (-6,+\infty)

3 0
3 years ago
Use transformations to solve the equation. c • 5 = 30 A. c = 5 B. c = 6 C. c = 150 D. c = 180
zmey [24]
C * 5 = 30
   
Divide both sides by 5 

c = 6
5 0
2 years ago
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