the sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less tha
n first . What equation can be used to solve the problem
1 answer:
No. 1 = x
No. 2 = 2x+7
No. 3 = x-12
Answer:
x+(2x+7)+(x-12) = 131
From there you solve to get the numbers:
34, 75 and 22
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