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2 years ago

Which option is an even function?

Mathematics

1 answer:

Grace [21]2 years ago

4 0

The correct answer is option D. Which is the even function is f (x) = x⁴.

<h3>What is an even function?</h3>

The function in which when the sign of the input variable is changed the output remains the same is called the even function. Mathematically we can write it as f(x) = f(-x ).

let us check the given four options:-

A f(x) = √x ; f(-x) = √-x here f(x) ≠ f(-x)

B f(x) = x ; f(-x) = -x here f(x) ≠ f(-x)

C f(x) = x³ + 1 ; f(-x) = -x³ + 1 here f(x) ≠ f(-x)

D f(x) = x⁴ ; f(-x) = (-x)⁴ = x⁴ here f(x) = f(-x)

We can see that in the option D the f(x) = x⁴ is an even function because f(x) = f(-x).

Therefore the correct answer is option D. Which is the even function is f (x) = x⁴.

To know more about even functions follow

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Step-by-step explanation:

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Gnesinka [82]

Answer:

Step-by-step explanation:

The formula for finding the midpoint of two coordinates is expressed as;

M(X,Y) = $(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})$

Given the coordinates c(-4,5) and d(-1,-4), x1 = -4, y1 = 5, x2 = -1 and y2 = -4.

For the X coordinate of the midpoint

X = x1+x2/2

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3 years ago

Cos(-170°) = _____<br><br> -cos10°<br> cos10°<br> cos(-10°)

ikadub [295]

<em>The right answer for:</em>

<h2>Explanation:</h2>

The cosine function is an even function, which means that for every point $(x,y)$ on the graph of $y=cos(x)$ then the point $(-x,y)$ also lies on the graph of the function. In other words, we can write:

$cos(-170^{\circ})=cos(170^{\circ})$

But:

$170^{\circ}=180^{\circ}-10^{\circ}$

So:

$cos(170^{\circ})=cos(180^{\circ}-10^{\circ})$

By property:

$cos(a-b)=cosacosb+sinasinb \\ \\ a=180^{\circ} \\ \\ b=10^{\circ} \\ \\ cos(170^{\circ} )=cos(180^{\circ} -10^{\circ})=cos180^{\circ} cos10^{\circ} +sin180^{\circ} sin10^{\circ} \\ \\ cos(170^{\circ})=-cos(10^{\circ})+0 \\ \\ \boxed{cos(170^{\circ})=-cos(10^{\circ})}$

<h2>Learn more:</h2>

Trigonometric functions: brainly.com/question/2680050

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