Answer:
The maximum error in the calculated area of rectangle is 5.4 cm².
Step-by-step explanation:
Given : The length and width of a rectangle are measured as 30 cm and 24 cm, respectively, with an error in measured of at most 0.1 cm in each.
To find : Use differentials to estimate the maximum error in the calculated area of rectangle ?
Solution :
The area of the rectangle is 
The derivative of the area is equal to the partial derivative of area w.r.t. length times the change in length plus the partial derivative of area w.r.t. width times the change in width.
i.e. 
Here, 
Substitute the values,



Therefore, the maximum error in the calculated area of rectangle is 5.4 cm².
9. You divide 1620 by 12 then my 15
<h2><u>Solution</u> :-</h2>
Given : Radius of cylinder = 8 m
Height = 4 m
Volume of cylinder = πr²h cu. units
= 22/7 × 8 × 8 × 4 m³
= 804.57 m³ (approx.)
Curved surface area = 2πrh sq. units
= 2 × 22/7 × 8 × 4 m²
= 201.14 m² (approx.)
Total surface area = 2πr(r + h) sq. units
= 2 × 22/7 × 8 (8 + 4) m²
= 2 × 22/7 × 8 × 12 m²
= 603.43 (approx.)
Answer:
X=-8
Step-by-step explanation:
<span>For a function "f" defined by an expression with variable theta, the implied domain of "f" is the set of all real numbers variable theta can take such that the expression defining the function is real. !</span>