Rotation about a point does not change any dimensions. C'D' = CD = 2.8 units.
It is true. Perpendicular lines are what we call to two lines that intersect together forming a right angle or an angle measuring 90 degrees. You can easily determine this if you see a horizontal and a vertical line intersect together.
Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x = 
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x = 
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
= 
+ 
,
x = 
... And squared is 11, making the area of this square 11 units².
Square H"G"F"E" is 6/4 or 3/2 times the size of square EFGH.
Use the following 4 transformations to map EFHG onto its image E"F"G"H":
1. Invert EFGH about y=1 so that it's numbering becomes HGFE, in the same order as its image.
2. Dilate EFGH by 3/2. This will make EFGH of the same area as E"F"G"H". Its center will be at (-4, 1).
3.Translate EFGH along x (horizontally to the left) by 2 units. This will line up EFGH with E"F"G"H" but it will be 10 units above its image.
4. Translate EFGH along y (vertically downward) by 10 units. This will map EFGH onto its image E"F"G"H".
Answer:
8x+64≥150
Step-by-step explanation:
$8 an hour is your variable, and 64 is added already. She needs at least $150, so that's greater than or equal to 150.
