A series of transformations maps EFGH onto its image.

Mathematics

1 answer:

Afina-wow [57]3 years ago

8 0

Square H"G"F"E" is 6/4 or 3/2 times the size of square EFGH.

Use the following 4 transformations to map EFHG onto its image E"F"G"H":
1. Invert EFGH about y=1 so that it's numbering becomes HGFE, in the same order as its image.
2. Dilate EFGH by 3/2. This will make EFGH of the same area as E"F"G"H". Its center will be at (-4, 1).
3.Translate EFGH along x (horizontally to the left) by 2 units. This will line up EFGH with E"F"G"H" but it will be 10 units above its image.
4. Translate EFGH along y (vertically downward) by 10 units. This will map EFGH onto its image E"F"G"H".

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hichkok12 [17]

Hello there! Your answer is 2.

When we are given this problem: x + 3 = 8x - 11 we are solving for the value of X. We want to isolate all like terms on one side of the equation. To do this, let's add 11 to the left side so the - 11 cancels out on the right.

x + 3 + 11 = 8x - 11 + 11 - After this, add like terms. (so 3 + 11 and - 11 + 11)

x + 14 = 8x - Now, negative 11 plus positive 11 have canceled each other out, we have to subtract x from the left side.

x - x + 14 = 8x - x

14 = 7x - Our last step is do divide both sides of the equation by 7 to finish isolating x.

14/7 = 7/7x

2 = x.

This is your final answer!

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