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BabaBlast [244]
2 years ago
5

How does understanding of 5 x 12 = 60 help to solve for the product of 5 x 120? Explain in words

Mathematics
2 answers:
Lorico [155]2 years ago
7 0

3) Number: 640,700

   the value of 4 in this number is 40,000

Number: 64,070

the value of 4 in this number is 4,000

So, times greater: 40,000 ÷ 4,000 = 10 times greater.

4)

The multiplication, 5 × 12 = 60. So, 5 × 120 = 600.

There is an extra zero at the very last of the result as '120' was multiplied with 5 instead of '12' which does not have zero at last which changes the result.

Similar cases with: 5 × 10 = 50. So, 5 × 100 = 500.

Lynna [10]2 years ago
6 0

Answer:

c6

Step-by-step explanation:

justjustcancacanjustadda0totheproduct of5cxwewtogetthesameresultasx1totoandtimes

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R= 2s-6t 5 divided by 2, solve for s
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R = (2s - 6t + 5)/2
2R = 2s - 6t + 5
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s = (2R + 6t - 5)/2
8 0
2 years ago
What is 75% as a fraction in simplest form
ludmilkaskok [199]
75% = 75/100÷ 5= 15/20 ÷5= ¾. does this help? hope it does
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7 0
2 years ago
X + 3 = 15<br> Solve the equation and check for the solution
dangina [55]

Answer:

x=12

Step-by-step explanation:

move the 3 to the other side to get x by itself.

check: 12 + 3 = 15

3 0
2 years ago
Read 2 more answers
Solve each system by elimination.<br> 10x-6y=-8<br> -10x+6y=8
Step2247 [10]

Answer:

Infinitely Many Solutions

Step-by-step explanation:

10x-6y=-8\\-10x+6y=8\\\0 = 0\\

4 0
2 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
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