What is the value of (-2)4?<br> What is the value of (-2) squared4

GrogVix [38]

The circumference of a circle with radius $r$ is $2\pi r$ . If the length of the radius is tripled, then the circumference becomes $2\pi(3r)=3\cdot2\pi r$ , which is just 3 times the original circle's circumference.

4 0

3 years ago

Find the perimeter of a regular pentagon with each side measuring 6cm.

Black_prince [1.1K]

Answer:

30cm

Step-by-step explanation:

Perimeter of a Pentagon=5L

P=5×6cm=30cm

6 0

2 years ago

Y=|x+4|-3<br> What are the X values for this problem

Allushta [10]

The x values can be anything, the y value is dependant on the x and your x value would depend on the scale of your x axis

3 0

3 years ago

Read 2 more answers

Graph the image of this figure after a dilation with a scale factor of centered at the origin.

kvv77 [185]

A picture of the dilated figure with its points at (-2, 10), (2, 6), and (-8, 4) is provided.

<h3 /><h3>What exactly is dilation?</h3>

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.

The complete question is;

"Graph the image of this figure after a dilation with a scale factor of 2 centered at (2, 2) .

Use the polygon tool to graph the dilated figure."

The center of dilation and figure are first translated, making the origin the center of dilation.

We map every point because the point (2, 2), which is our center of dilatation, must be translated left 2 and down 2 to become the origin.

(x, y)→(x-2, y-2)

Each point will be multiplied by two when the scale factor is two, giving us the rule.

(x, y)→(2x-4, 2y-4)

In order to return the figure to its original location, we must translate it right 2 and up 2; this gives us the rule.

(x,y)→(2x-4+2, 2y-4+2) = (2x-2, 2y-2)

At the top of the original figure, the first point is (0, 6). When we use the transformation, we get

(0, 6)→(2*0-2, 2*6-2) = (0-2, 12-2) = (-2, 10)

The pre-rightmost image's point is (2, 4). The results of using the transformation rule are;

(2, 4)→(2*2-2, 2*4-2) = (4-2, 8-2) = (2, 6)

The pre-leftmost image's point is at (-3, 3). The transformation rule being applied, w

(-3, 3)→(-3*2-2, 3*2-2) = (-6-2, 6-2) = (-8, 4)

Hence,an picture of the dilated figure with its points at (-2, 10), (2, 6), and (-8, 4) is provided.

To learn more about dilation, refer to

brainly.com/question/13176891.

#SPJ1

7 0

1 year ago

Find the coordinates of the point at which the normal to the curve y = x ^ 2 at x = 1 meets the curve again

sveta [45]

Answer:

$(-\frac{3}{2},\frac{9}{4})$

Step-by-step explanation:

A normal line is a line perpendicular to the tangent line, so we must take the derivative of the function to find the slope of the tangent line, and then take the opposite reciprocal of this slope, to find the slope of the normal line. The equation of a normal line will be in the form of $y=mx+b$ :

$f(x)=x^2\\\\f'(x)=2x\\\\f'(1)=2(1)\\\\f'(1)=2$

Hence, the opposite reciprocal is $-\frac{1}{2}$ , which is our slope for the normal line. Now, we find the y-intercept by plugging in the given coordinate point $(1,1)$ since $f(1)=1^2=1$ :

$y=-\frac{1}{2}x+b\\\\1=-\frac{1}{2}(1)+b\\ \\1=-\frac{1}{2}+b\\ \\b=\frac{3}{2}$

Thus, the equation of the normal line is $y=-\frac{1}{2}x+\frac{3}{2}$ . Using this information, we can now find the coordinates where the normal of the curve at x=1 meets the curve again: