Answer:
import java.util.Scanner;
import java.lang.*;
class Main
{
public static void main(String args[])
{
int n;
//For capturing the value of n
Scanner scanner = new Scanner(System.in);
System.out.println("Enter the value of n:");
//The entered value is stored in the var n
n = scanner.nextInt();
int k=1;
printnum(n,k);
}
public static void printnum(int n,int k)
{
if(n%2==0)
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
else
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
n--;
if(n<=1)
{
System.exit(0);
}
else
{
printnum(n,k+1);
}
}
}
Explanation:
The program is self explanatory.
The most common was is your phone
It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.
<h3>What is pop operation? </h3>
The removal of an element is referred to as a pop operation. Again, because we only have access to the element at the top of the stack, we can only remove one element. We simply take the top of the stack off.
A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.
The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.
Thus, the correct option is a.
For more details regarding pop operation, visit:
brainly.com/question/15172555
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