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kykrilka [37]
3 years ago
12

All of the following are vertical alignment options except __middle , top, center, or_bottom_.

Computers and Technology
1 answer:
Dominik [7]3 years ago
3 0
<span>All of the following are vertical alignment options except middle, whereas top, center, and bottom are vertical alignment options. </span>
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Most email clients contain a ____ that allows the user to read an email message without actually opening it
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Most email clients contain a "subject" that allows the user to read an email message without actually opening it.
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Given a integer, convert to String, using String Builder class. No error checking needed on input integer, However do read in th
Gennadij [26K]

Answer:

The program in Java will be:

// Java program to demonstrate working parseInt()  

public class GFG  

{  

   public static void main(String args[])  

   {  

       int decimalExample = Integer.parseInt("20");  

       int signedPositiveExample = Integer.parseInt("+20");  

       int signedNegativeExample = Integer.parseInt("-20");  

       int radixExample = Integer.parseInt("20",16);  

       int stringExample = Integer.parseInt("geeks",29);  

 

       // Uncomment the following code to check  

       // NumberFormatException  

 

       //   String invalidArguments = "";  

       //   int emptyString = Integer.parseInt(invalidArguments);  

       //   int outOfRangeOfInteger = Integer.parseInt("geeksforgeeks",29);  

       //   int domainOfNumberSystem = Integer.parseInt("geeks",28);  

 

       System.out.println(decimalExample);  

       System.out.println(signedPositiveExample);  

       System.out.println(signedNegativeExample);  

       System.out.println(radixExample);  

       System.out.println(stringExample);  

   }  

}

7 0
3 years ago
Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn c
barxatty [35]

Answer:

#include <string>

#include <iostream>

using namespace std;

int main() {

string userInput;

getline(cin, userInput);

// Here, an integer variable is declared to find that the user entered string consist of word darn or not

int isPresent = userInput.find("darn");

if (isPresent > 0){

cout << "Censored" << endl;

// Solution starts here

else

{

cout << userInput << endl;

}

// End of solution

return 0;

}

// End of Program

The proposed solution added an else statement to the code

This will enable the program to print the userInput if userInput doesn't contain the word darn

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En la historia del Computador porque se caracteriza la primera generación? *
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