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mafiozo [28]
2 years ago
8

Describe the following pattern:1;8;27;64;125​

Mathematics
1 answer:
dolphi86 [110]2 years ago
7 0
Answer: All these numbers are the cube of consecutive numbers ,the cube of 1 is 1, the cube of 2 is 8 ,3 is 27 ,4 is 64 and so the next number which is 5 , it's cube will be 125 and so the series will be 1, 8, 27, 64, 125 ,216 and so on…!
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Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

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           p = probability of success which in our question is % of defective

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<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

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                  =  \binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}

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                  =  <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

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