Question

Consider two cells, the first with al and ag electrodes and the second with zn and ni electrodes, each in 1. 00 m solutions of their ions. If connected as voltaic cells in series, which two metals are plated, and what is the total potential, e∘ ?.

Answer 1

In the first cell, the metal silver (Ag) is plated and in the second cell, the metal nickel (Ni) is plated.

What are electrodes?

Electrodes may be defined as electrical conductors operated to construct connections with a nonmetallic part of a circuit. An electrode is referred to as an anode or a cathode depending on the direction of the flow of electrons.

In the first cell,

$Ag^+ + e^-$ → Ag      $E^0$ = 0.80V.

$Al^3^+ + 3e^-$ → Al     $E^0$ = -1.66V.

In the second cell,

$Zn^2^+ + 2e^-$ → Zn    $E^0$ = -0.76V.

$Ni^2^+ + 2e^-$ → Ni     $E^0$ = -0.25V.

Since the cells are connected in series:

$E_t_o_t_a_l$ > 0.

∴The total potential, $E^0_t_o_t_a_l$ = $E^0 _c_e_l_l1- E^0 _c_e_l_l2$

= (0.80 + 1.66 ) V - (0.25 +0.76 ) V

= 2.97 V

Therefore, it is well described above.

To learn more about Electrochemical potential, refer to the link:

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