Answer:
3168
Step-by-step explanation:
Here, we have s combination problem as we are selecting. The question is quite straightforward.
What the director needs to do is simply select 10 males from the total 15 males and also select 8 females from the total 11 females and add the results.
To select 10 from 15, we simply compute as 15C10 which equals 3003 ways
To select 8 from 11, we simply compute 11C8 which equals 165 ways
We simply add both to get the numbers of possible casts which is 3003 + 165 = 3168 possibilities
Answer: 1/2
When looking at a graph, you need to follow the formula rise/run. This means that between two points, you need to find the distance up and down/left and right.
Looking at points (0,2) and (2,3), I see that the second point is 1 point higher. Let’s add that in for rise.
Rise/run
1/run
Now for run. The second point is 2 points to the right of the first one. Let’s add that in.
1/2
This is your answer! Hope this helps comment below for more questions :)
Answer:
Check the explanation
Step-by-step explanation:
in this particular type of problems,we have to go with the cases.we know there would be a 50 odd-even pairs between 1 and 100.
1st case: 1 is placed at the head position of given set S.so there is a chance of only one even number beside 1.so there are 50×98!
2nd case: 1 is placed at tail position of S.so there is again a chance of one even number beside 1. so there are
50×98!
3rd case: 1 is placed neither at head nor at tail.1 can be at rest 98 places.lets fix the place of 1.then the choices are difference between permuting all the numbers and 1 surrounded by two odd numbers.
i.e., 99! - 49p2 ×97!
so total choces are = 2×50×98! + 99! - 49p2 × 97!
= 7448 × 97! + 99!
Answer:
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Step-by-step explanation: