Ask question

Ask question

All categories

3 years ago

7

A bracelet is exactly 6.97 cm across from one side to the other, through the center. What is the approximate area of the bracele

t?(Hint draw a picture and label 6.97 on the picture)

1 answer:

Vadim26 [7]3 years ago

3 0

Answer:

≈ 38.14 cm²

Step-by-step explanation:

Diameter of circle= 6.97 cm

Area of circle = ?

Area = πr² = πd²/4 =
3.14*(6.97)²/4 ≈ 38.14 cm²

You might be interested in

The graph of f(x) = 13* - 6 is shown below.g(x) is a transformation of f(x).

sergejj [24]

Answer:

your answer is proably 15 i dont really know

Step-by-step explanation:

8 0

3 years ago

Charlie walked a distance of 500 meters to school. It took him 5 minutes to arrive at school from home. What is his average spee

Nikolay [14]

Answer:

100 meters per minute

Step-by-step explanation:

Find his average speed by dividing the distance he walked by the number of minutes it took him:

500/5

= 100

So, his average speed was 100 meters per minute

6 0

3 years ago

Read 2 more answers

The difference between the MDC and the LDC's

Contact [7]

Answer: MDCs have advanced socially and economically, whereas LDCs are in the early stages of development.

8 0

2 years ago

Which is a way to break the irregular figure into shapes

STALIN [3.7K]

Answer:

1 parallelogram and 1 rectangle

Step-by-step explanation:

ajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhvdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjhajkdfalksjdfhhsldfjhaskdhflksjdhfaljhfieufhlkjdsfkaljhfkajhlifkajhfalkjh

8 0

3 years ago

Read 2 more answers

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

3 years ago