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anastassius [24]
2 years ago
11

Select all the shapes below that have a constant cross-section between a

Mathematics
1 answer:
meriva2 years ago
5 0

The shapes below that have a constant cross-section between a pair of faces are cylinder, cube, sphere, hexagonal, and prism.

<h3>What is the definition of geometry?</h3>

It is concerned with the geometry, region, and density of various 2D and 3D shapes.

A cylinder is a closed solid with two parallel circular bases and a curving surface connecting them.

The shapes have a constant cross-section between a pair of faces like a cylinder.

Hence,cylinder, cube, sphere, hexagonal, and prism are the forms below that have a constant cross-section between a pair of faces.

To learn more about geometry, refer to brainly.com/question/7558603.

#SPJ1

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3.2 cm on the map correspond to 4 km in the actual distance?
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What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

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