1a) A = 4πpw
/4πw = /4πw
A / 4πw = p
1b) A = 4πpw
22 = 4πp(2)
p = 11/4π (≈0.87)
2a) P = 2πr + 2x
P - 2x = 2πr
/2π /2π
P-2x / 2π = r
2b) P = 2πr + 2x
440 = 2πr + 2(110)
r = 110/π (≈35.014)
To solve for the confidence interval for the true average
percentage elongation, we use the z statistic. The formula for confidence
interval is given as:
Confidence interval = x ± z σ / sqrt (n)
where,
x = the sample mean = 8.63
σ = sample standard deviation = 0.79
n = number of samples = 56
From the standard distribution tables, the value of z at
95% confidence interval is:
z = 1.96
Therefore substituting the known values into the
equation:
Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)
Confidence interval = 8.63 ± 0.207
Confidence interval = 8.42, 8.84
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Two lines intersect in one point.
Answer:
33.85 units^2
Step-by-step explanation:
you must first draw the triangle on the plane using the equations (see
attached file), you will have a right angle triangle with a height of 192 and a base of 6.
then you calculate the angle with the tangent function = 88.21
Then you use the small triangle to find the value of a (see attached file).
Finally, you propose an equation for X to find one of the sides of the triangle, once you have x squared it, and you already have the area,
i attached procedure
The answer for this problem would be x equal to 430 cm and y is equal to 325. This is computed by establishing the equations. This first equation based on first statement would be x = 15 + y and the second would be 5x = 3y + 525. Then it is solve as follows:
5x = 3y + 525