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2 years ago

Nathan enlists the help of a collector's

Mathematics

1 answer:

klemol [59]2 years ago

8 0

Take a pic of this in Brainly and you’ll see the answers

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Simplify [-2.8] please help me how to simplify this math proplem??????<br /><br />

Karolina [17]

In fraction form the answer would be -2 4/5.

7 0

3 years ago

Read 2 more answers

Solve equation, check for extraneous solutions

fiasKO [112]

Start with

$1=\dfrac{1}{n^2}+\dfrac{n^2-4n-5}{3n^2}$

We observe that both fractions are not defined if $n=0$ . So, we will assume $n \neq 0$ .

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

$1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}$

We multiply both sides by $3n^2$ :

$n^2-4n-2=3n^2$

We move everything to one side and solve the quadratic equation:

$2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1$

We check the solution:

$1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0$

which is true

8 0

3 years ago

PLEASE HELP, IM TIMED!!!!!!

Andru [333]

Answer:A,B,E

Step-by-step explanation:

7 0

3 years ago

Can someone please answer this question please answer it correctly and please show work please help me I need it

Olin [163]

Answer:

9-3=6

Step-by-step explanation:

Line from left to right: number 9 (absolute value)

Line from right to left: number 3 (absolute value)

Overall: 9-3=6

We used the minus sign for 3 because the corresponding line is oriented in the opposite direction.

4 0

3 years ago

Read 2 more answers

The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18

Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

$\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96$

So, 95% confidence interval becomes,

$(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)$

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0

3 years ago