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enot [183]
1 year ago
8

NEED THIS DONE ASAP!! Thank you!!​

Mathematics
1 answer:
g100num [7]1 year ago
7 0

Answer:

\overset{\frown}{WX}= 66^{\circ}

Step-by-step explanation:

<u>Inscribed Angle Theorem</u>

The measure of an <u>inscribed angle</u> is half the measure of the <u>intercepted arc</u>.

First, use the Inscribed Angle Theorem to calculate the measure of arc WY.

  \displaystyle \angle WXY=\dfrac{1}{2} \overset{\frown}{WY}

\implies 57^{\circ}=\dfrac{1}{2} \overset{\frown}{WY}

\implies \overset{\frown}{WY}= 2 \cdot 57^{\circ}

\implies \overset{\frown}{WY}= 114^{\circ}

Assuming XY is the diameter of the circle:

\implies \overset{\frown}{WY}+ \overset{\frown}{WX}= 180^{\circ}

\implies 114^{\circ} + \overset{\frown}{WX}= 180^{\circ}

\implies \overset{\frown}{WX}= 180^{\circ} - 114^{\circ}

\implies \overset{\frown}{WX}= 66^{\circ}

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EXPLANATION

The diagonal of the rectangular painting is 62cm.

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The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

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