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Burka [1]
2 years ago
6

Suppose y varies directly as x², and y = 160 when x = 4. Find y when x = 6.

Mathematics
1 answer:
labwork [276]2 years ago
7 0

<u>Finding the constant of proportionality</u> :

  • y = kx²
  • 160 = k(4)²
  • k = 10

<u>Finding y when x = 6</u> :

  • y = 10(6)²
  • y = 10(36)
  • y = 360

The value of y is <u>360</u> when x = 6.

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AfilCa [17]
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761280 / 29280 = 26 years

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4 0
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5 0
3 years ago
Which quadratic equation fits the data in the table? x -5,-2,-1,0,3,4,6 y 33,9,5,3,9,15,33
mojhsa [17]

Answer:

y = x² − x + 3

Step-by-step explanation:

Quadratic equation is:

y = ax² + bx + c

Pick three points and plug in.  I'll choose (-2, 9), (-1, 5), and (0, 3).

9 = a(-2)² + b(-2) + c

5 = a(-1)² + b(-1) + c

3 = a(0)² + b(0) + c

9 = 4a − 2b + c

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9 = 4a − 2b + 3

5 = a − b + 3

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0 = a − b − 2

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b = a − 2

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0 = 4a − 2a + 4 − 6

0 = 2a − 2

a = 1

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y = x² − x + 3

6 0
3 years ago
Solve pls brainliest
BigorU [14]
Have a great day!!!!

7 0
2 years ago
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Simplify the expression. <br><br> -1/2 + 1/6
sukhopar [10]
-1/2 = -3/6

-3/6 + 1/6 = -2/6

-2/6 = -1/3

-1/3 is your answer

hope this helps
8 0
3 years ago
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