The decay constant is i 0.1155, and there would be 16 mg left after 24 hours.
The relationship between the half-life, T₀.₅, and the decay constant, λ, is given by
T₀.₅ = 0.693/λ.
Solving for λ, we will multiply both sides by λ first:
(T₀.₅)(λ) = 0.693
Since we know the half life is 6 hours, this gives us:
6λ = 0.693
Dividing by 6, we have
λ = 0.693/6 = 0.1155.
The decay constant will be k in our decay formula, and N₀, the original amount of substance, is 250:
N(24) = 250e^(-0.1155*24) = 15.6 ≈ 16
Answer:
x is 7
Step-by-step explanation:
-3-(-8)-(-2) = x
7 = x
So, if the legs are a and b and the hypothuse is c then
a²+b²=c²
the distance bewteen the points is the hyptohuse
the legs are the distances between th x and y values
so
(7,11) and (-1,5)
distances between the x values are 1 leg
that is from 7 and -1, a distance of 8 units
distances betweeen the y values are the other leg
that is from 11 to 5
that is 6 units
a²+b²=c²
8²+6²=c²
64+36=c²
100=c²
sqrt both sides
10=c
the distance between them is 10 units
Answer:
9
Step-by-step explanation:
3*3 = 9
if that's what you're asking