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rjkz [21]
1 year ago
9

a test for a certain drug has a 0.1% probability of producing a false positive. if a company hired 500 drug-free employees, what

is the probability of obtaining at least 1 false positive?
Mathematics
1 answer:
Natasha_Volkova [10]1 year ago
6 0

The probability of obtaining at least 1 false positive if the number of employees is 500 is 0.5

Probability

In the statistics concept, the probability refers the possible number of way of happening the particular event.

Given,

A test for a certain drug has a 0.1% probability of producing a false positive.

Here we need to find  the probability of obtaining at least 1 false positive if  a company hired 500 drug-free employees.

In the given question, we have the following values,

=> number of employees = 500

=> Probability of false positive = 0.1%

So, the probability of obtaining at least 1 false positive is calculated as,

=> 500 x 0.1/100

=> 5 x 0.1

=> 0.5

Therefore, the probability of obtaining at least 1 false positive is 0.5.

To know more about Probability here.

brainly.com/question/11234923

#SPJ4

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Answer:

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Step 1: Add -12a to both sides.

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Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

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Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

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adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

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Step-by-step explanation:

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