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svp [43]
2 years ago
11

Given that y is an integer, find all values of y such that y< 6

Mathematics
1 answer:
Anni [7]2 years ago
8 0

Answer:

Values: 3,4,5

Step-by-step explanation:

I hope this helps:)

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Explain the pattern that you notice when dividing by 10,100 and 1,000
Vanyuwa [196]

Answer:

Step-by-step explanation:

An easier way to do this type of problem, is to break it down,

10,000/1,000 is the BIG SCARY Problem, think of it like 10/1,\

1 goes into 10, 10 times,

So, what is 1,000x10?

10,000

Answer, 10

Pattern, is that is decreases by 1,000 every time and now you know

3 0
2 years ago
What is the volume of the sphere in terms of π?
timama [110]

Answer:

Step-by-step explanation:

8 0
4 years ago
Christian can paint a car in 6 hours. Carter can paint the same car in 3 hours. If they work together, how long will it take to
just olya [345]
It would take them 2 hours to paint the whole car

5 0
3 years ago
Read 2 more answers
Brainliest answer . Help please answer and pls don't answer if you don't understand .
-Dominant- [34]

Answer:

1/2

Step-by-step explanation:

We do change in y over change in x

<u>Formula for Rate of Change on Slope</u>

y2-y1/x2-x1

<u>For Y</u>

We use coordinate (-2, -4)

-4--2

= -2 - -4

= 2

<u>For X</u>

We use coordinate (0, -4)

0 -- 4

= 0 + 4

= 4

Now we put y over x to find the rate of change in slope

2/4, simplified would be 1/2

5 0
3 years ago
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A random sample of medical files is used to estimate the proportion p of all people who have blood type b.
makvit [3.9K]

Answer:

a) 106

b) 53

Step-by-step explanation:

Minimum required medical files can be found using the formula

n≥ p×(1-p) × (\frac{z}{ME} )^2 where

  • n is the minimum required medical files
  • p is the estimated proportion for blood type b
  • z is the corresponding z-score for two tailed 85% confidence level
  • ME is the margin of error in the estimation

For the case (a)

If there is no preliminary estimate for p, then it is estimated as p=0.5

corresponding z-score for two tailed 85% confidence level is 1.44

and ME is 0.07.

Putting all in the formula;

n≥ 0.5×0.5 × (\frac{1.44}{0.07} )^2  ≈ 106

For the case (b)

The only difference is p=\frac{13}{90}≈0.144

n≥ 0.144×0.856 × (\frac{1.44}{0.07} )^2  ≈ 53

7 0
4 years ago
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