Answer:\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( 5^{\frac{3}{2}} \right)^{-\frac{2}{3}}\implies 5^{-\frac{3}{2}\cdot \frac{2}{3}}\implies 5^{-1}\implies \cfrac{1}{5}\implies 0.2 \\\\[-0.35em] ~\dotfill
\bf (256^{0.5})^{1.25}\implies [(2^8)^{0.5}]^{1.25}\implies [2^{8\cdot 0.5}]^{1.25}\implies [2^4]^{1.25}\implies 2^{4\cdot 1.25} \\\\\\ 2^5\implies 32 \\\\[-0.35em] ~\dotfill\\\\ ( 81^{-\frac{1}{6}} )^{\frac{3}{2}}\implies [(3^4)^{-\frac{1}{6}} ]^{\frac{3}{2}}\implies 3^{4\cdot -\frac{1}{6}\cdot \frac{3}{2}}\implies 3^{-\frac{12}{12}}\implies 3^{-1} \\\\\\ \cfrac{1}{3}\implies 0.33...
Step-by-step explanation: I don’t really know about inequalities can y’all help?
Step-by-step explanation:
first find two numbers u multiply to get 7 and add to get 8: (1×7)=7,(1+7)=8
so in the first bracket u put (x +1) n in the other (x+7)
ans: (x+1)(x+7)
Answer:
Step-by-step explanation:
C.) because 2/3=.666 then .666/2 = .333 so .333 times 6/5 equals .4 which is the same as 2/5.
