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VikaD [51]
2 years ago
11

Write the logarithmic expression as a single logarithm with coefficient , and simplify as much as possible. Assume that all vari

able expressions represent positive real numbers.
1/2ln(b^2+1)-1/2ln(b+1)
Mathematics
1 answer:
Allushta [10]2 years ago
4 0

Answer:

hope you can understand

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sashaice [31]
A) For the equation y=- \frac{1}{2}x+3, the slope is - \frac{1}{2}.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if m=- \frac{1}{2}, the slope is  - \frac{1}{2}.

B) Since this equation is in the same form, you just find what m is equal to.
Since m=2, that's the slope.

For the solution, set y=- \frac{1}{2}x+3 equal to y=2x-4, so it would be put together like this:
y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667
So your answer is -4.667.
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If you round it to the nearest ten-thousand, your answer would be 30,000.

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Answer:

It will have complex and different roots.

Step-by-step explanation:

The solution is attached in the image below:

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Which equation represents the line that passes through (–6, 7) and (–3, 6)?
Softa [21]

Answer:

The equation that represents the line that passes through (-6,7) and (-3,6) is: y = -1/3x + 5

Step-by-step explanation:

The equation of line for point=slope form is

y-y₁ = m(x-x₁)

Finding Slope m:

m= y₂-y₁/x₂-x₁

here y₂= 6,y₁= 7,x₂= -3,x₁= -6

m = 6-7/-3-(-6)

m = -1/-3+6

m = -1/3

The slope m = -1/3 and considering point (-6,7) the equation is:

y-y₁ = m(x-x₁)

y-7 = (-1/3)(x-(-6))

y-7 = -1/3(x+6)

y-7 = -1/3x -2

y = -1/3x-2+7

y = -1/3x + 5

So, the equation that represents the line that passes through (-6,7) and (-3,6) is: y = -1/3x + 5

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