All categories

4 years ago

Two numbers are in the ratio of 3 to 4. If the minor is 27, find the sum of both.

Mathematics

2 answers:

andre [41]4 years ago

7 0

Answer:

Sum = 63

$\boxed{ x = 36}$

Step-by-step explanation:

3 : 4

It says that the 1st part (3) is 27

27 : x (We've to find the major)

Creating a proportion:

=> 3 : 4 = 27 : x

Product of Means = Product of Extremes

=> 3 * x = 27 * 4

=> 3x = 108

Dividing both sides by 3

=> x = 36

The sum of both is 27+36 = 63

german4 years ago

4 0

Answer:

Step-by-step explanation:

First we must find the missing number, for that we apply a simple rule of three:

3. 4

27 ------ x

x = 27 (4) / 3 = 36

Now we just do the sum:

27 + 36 = 63

You might be interested in

JANITIA IS 15 YEARS OLD AND HER BROTHER IS 5 YEARS. WHAT IS THE RATIO OF JANTIA AGE TO HER BROTHER AGE

riadik2000 [5.3K]

Answer:

3:1

Step-by-step explanation:

15:5 = 3:1

5 0

2 years ago

Read 2 more answers

Simplify (5+22)×(35-27)+6 squared

blagie [28]

Answer:

Step-by-step explanation:

5+22=27

35-27=8

6squared=36

27+8+36=71

8 0

3 years ago

In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

Paha777 [63]

Answer:

0.3114

Option d is right

Step-by-step explanation:

Let X be the time spent on a treadmill in the health club

Given that research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes

Also given that X is normal

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

$= P(30$

round off to two decimals tog et

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill is 0.31

Hence option d is right

3 0

4 years ago

<img src="https://tex.z-dn.net/?f=%28v%2B6%29%5E%7B2%7D%3D2v%5E%7B2%7D%2B14v%2B12" id="TexFormula1" title="(v+6)^{2}=2v^{2}+14v+

timofeeve [1]

Answer:

v=-6 or 4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

This is really confusing me: Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$

3 0

3 years ago