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andreev551 [17]
2 years ago
9

For the functions given below, find and simplify completely: g(x+h)-g(x)/h (here, h is some parameter)

Mathematics
1 answer:
maksim [4K]2 years ago
4 0

Answer:

  a.  2

  b.  4x -1 +2h

Step-by-step explanation:

We can find the difference quotient for the given cases by first solving for the difference quotient in the general case. That solution can then be applied to the given cases.

__

<h3>general solution</h3>

For f(x) = ax² +bx +c, the difference quotient is ...

  \dfrac{f(x+h)-f(x)}{h}=\dfrac{(a(x+h)^2+b(x+h)+c)-(ax^2+bx+c)}{h}\\\\=\dfrac{(ax^2+2axh+ah^2+bx+bh+c)-(ax^2+bx+c)}{h}=\dfrac{2axh+ah^2+bh}{h}\\\\=\underline{2ax+b+ah}

__

<h3>a.</h3>

For g(x) = 2x+6, we have a=0, b=2, c=6. Substituting these values into the above formula, we find ...

  (g(x+h) -g(x))/h = 2·0·x² +2 +0·h

  (g(x+h) -g(x))/h = 2

__

<h3>b.</h3>

For g(x) = 2x² -x, we have a=2, b=-1, c=0. Substituting these values into the above formula, we find ...

  (g(x+h) -g(x))/h = 2·2·x +(-1) +2·h

  (g(x+h) -g(x))/h = 4x -1 +2h

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Expand and simplify (x+2) (x+3) (x+4)
NikAS [45]

Answer:

3x+9

Step-by-step explanation:

1(x+2) +1(x+3) +1(x+4)

<em>x+2+x+3+x+4</em>

<em>x+x+x+2+3+4</em>

<u><em>3x+9</em></u>

8 0
3 years ago
How many terms are in the exspression 4{8+3x]
slava [35]

2 terms

Step-by-step explanation:

4[8+2x]

=4*8+4*2x

=32+8x

therefore there are 2 terms

hope it helps u if yes pls mark brainliest

8 0
3 years ago
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8 0
3 years ago
4.4.3 Test (CST) Continuous Probability Distributions
Zanzabum

Answer:

B

Step-by-step explanation:

We have that for a normal distribution, the value of z can be calculated using the following formula:

z = (x - m) / sd

where x is the value to evaluate, m the mean and sd the standard deviation, we have those values x = 15.3, m = 17.4 and sd = 3.2

if we replace we have:

z = (15.3 - 17.4) /3.2

z = -0.65625

if we round to 2 decimal places, it would be -0.66, that is, the answer is B.

8 0
3 years ago
Silas tosses a football with an initial velocity of 10 ft/s from an initial height of 6 ft. What is the maximum height the ball
SSSSS [86.1K]
Sounds like a physics problem

basically we can simlpify it to this:
we toss something straight up with initial velocity 10ft/sec, assuming gravity kicks in, what is max height?

we can use the kinematic equation v_{f}^2=v_{0}^2+2ad
v_f is final velocity
v_0 is initial velocity
a is acceleration due to gravity
d=distance traveled

if we say he tosses it straight up then when it  reaches max height, v_f=0
and v_0=10 \frac{ft}{s}

and we know that a=-32.174 \frac{ft}{s^2}

so solving for d

<span>v_{f}^2=v_{0}^2+2ad
</span><span>v_{f}^2-v_{0}^2=2ad
</span><span>\frac{v_{f}^2-v_{0}^2}{2a}=d
plug the numbers in
</span>
\frac{(0)^2-(10 \frac{ft}{s})^2}{2(-32.174 \frac{ft}{s^2})}=d
1.5540498539193137315845092310561 ft=d

we add that to the initial 6ft
so total of 7.5540498539193137315845092310561 ft max height
about 7.6ft
7 0
3 years ago
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