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TiliK225 [7]
2 years ago
7

A beverage company produces cans of lemonade. According to the label a can contains a volume of 375mL of lemonade. A consumer gr

oup tested this claim by measuring the volume of lemonade in 2,500 cans. They found that the volume was normally distributed with a standard deviation of 5mL and a mean of 372mL.
If a can is chosen at random, find:

P (its volume is ≥382mL)
Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

The probability that the volume of a can chosen at random is ≥382 is 0.47725

<h3>Normal distribution probability</h3>

Probability is the likelihood or chance that an event will occur. For the given question, we need to calculate the  z value as shown;

z=\dfrac{x-\mu}{\sigma}

Given the following parameters

x=382mL\\\mu (mean)=372mL\\\sigma(S.D)=5mL

Substitute

z=\dfrac{382-372}{5} \\z=\dfrac{10}{5}\\ z=2

In order to calculate the probability that the volume of a can chosen at random is ≥382, we will look for (z≥2)

z≥2 according to probability table is equivalent to 0.47725

Learn more on normal distribution here: brainly.com/question/26822684

#SPJ1

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Step-by-step explanation:

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If a rectangle has a base of 6 units, and a height of 8 units, what is its area?
Morgarella [4.7K]

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PLEASE HELP MEEE! Simplify 6! − 3!
denpristay [2]

The simplified form of the expression 6! − 3! when it is simplify using the properties of factorial is 3!((6x5x4) − 1).

<h3>What is the simplified form of a term?</h3>

Simplified form of a term is the simplest way of expression the term, which is obtained  by applying the required operations of mathematics.

Factorial is the way to write the product of the numbers from its phase value to 1 in decreasing order. Suppose, the number is 3!. Then it can be written as,

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The expression which has to be simplified is,

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6! - 3!

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Thus, the simplified form of the expression 6! − 3! when it is simplify using the properties of factorial is 3!((6x5x4) − 1).

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Which function can be used to find the number of cells of bacteria in the population at time t
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Answer:

db / dt = kb  

this becomes b(t) = Ce^(kt)  

C = 100, the initial population  

P(1) = 420 = 100 e^(1k)  

4.2 = e^k  

ln 4.2 = k  

a) thus, b(t) = 100 e^(t ln 4.2)  

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Step-by-step explanation:

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