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kumpel [21]
2 years ago
13

How many positive 3-digit numbers have property that the first digit is at least three times the second digit?

Mathematics
1 answer:
ss7ja [257]2 years ago
3 0

The number of positive 3-digit numbers have a property that the first digit is at least three times the second digit is 285.

<h3>How to get the number?</h3>

Since restriction is set to the first digit, all you have to think is about the last two digits e.g if the first digit is one, the last two digits can only be zeros.

Thus, by the principle of multiplication, 1×1=1 way. If the first digit is 2, then the last digits can be either 1 or 0. You have 2×2=4 ways

For first digit 3, the last two digits can be 0,1 or 2. 3x3=9, there is a succinct pattern. Therefore, 1+4+9+16+25+36+49+64+81=285.

Learn more about numbers on:

brainly.com/question/251701

#SPJ1

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5 0
4 years ago
Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?
Colt1911 [192]

Answer:

Step-by-step explanation:

To use the quadratic formula, we must write the quadratic in standard form, viz:

2x^2 - 4x + 7 = 0

Start by calculating the discriminant.  That's b^2 - 4(a)(c).  Here,

a = 2, b = -4 and c = 7, and so the discriminant for this particular problem is

(-4)^2 - 4(2)(7), or 16 - 56, or 40.

Recall that  a positive discriminant indicates two real, unequal roots.

Now we write out the whole quadratic formula, with the appropriate constants inserted (see above):

       -(-4) ± √40          4 ± (√4)(√10)          4 ± 2√10

x = --------------------- = ----------------------  =  ---------------

               2(2)                        4                          4

                                    2 ± √10

which reduces to x = --------------

                                          2

6 0
3 years ago
Simplify completely 5х^3 + 10х^2 + 15х / 5x pleasseeeee HURRRRYYY
devlian [24]

Answer:   5x^{3} +x^{2} +3

Step-by-step explanation:

3 0
4 years ago
How many different 2-digit numbers are there with the following property:the tenth digit is greater than the units digit?
Serggg [28]

Answer:

45

Step-by-step explanation:

Simply start by listing out the numbers from smallest to largest.

We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45

7 0
2 years ago
Find the volume of the pyramid below. Hint: The base is a right triangle, so you will need to find
Aleks04 [339]

<u>Given</u>:

Given that the height of the pyramid is 12 units.

The base of the triangle is 8 units.

The height of the triangle is 6 units.

We need to determine the volume of the pyramid.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

A=\frac{1}{2} bh

where b is the base of the triangle and h is the height of the triangle.

Substituting the values, we get;

A=\frac{1}{2}(8)(6)

A=\frac{1}{2}(48)

A=24

Thus, the area of the triangle is 24 square units.

<u>Volume of the pyramid:</u>

The volume of the pyramid can be determined using the formula,

V=\frac{1}{3}AH

where A is the area of the triangle and H is the height of the pyramid.

Substituting the values, we get;

V=\frac{1}{3}(24)(12)

V=\frac{1}{3}(288)

V=96

Thus, the volume of the pyramid is 96 cubic units.

4 0
3 years ago
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