You have to use implicit derivative
dy / dx = y'
xy^3+y=3x
y^3 + 3xy^2 y' + y' = 3
[3xy^2 + 1) y'= 3 - y^3
3 - y^3
y' = ----------------- <-----------answer
3xy^2 + 1
Answer:
4(x - 2) + x = 5x + 8
Step-by-step explanation:
In an equation with a single variable, if that variable value is any integer divided by zero then it will have infinite numbers of solutions.
<h3> Example </h3>
4(x - 2) + x = 5x + 8
To solve this, we need to rearrange like terms to the same side.
4x - 8 + x = 5x + 8
4x + x - 5x = 8 - 8
5x - 5x = 0
x(5-5) = 0
x(0) = 0
x = 0 / 0
x = ∞
Since zero is in denominator , it means that the equation has infinite number of solutions.
Answer:
(5,10)
Step-by-step explanation:
(-10x + 7y = 20)8 -80x + 56y = 160
(8x - 6y = -20)10 + 80x - 60y = -200
-4y = -40
y = 10
Plug 1 in for y into the first equation
-10x + 7(10) = 20
-10x + 70 = 20
- 70 - 70
-10x = -50
x = 5
If this answer is correct, please make me Brainliest!
Greetings!Solve using the properties of equality:
Add
-5 to both sides.
Divide both sides by
3.
The Answer Is:Hope this helps.
-Benjamin
20 as 4 x 5 is 20 so there you hopefully