Question

Which is the graph of f(x)=√x?

Answer 1

Answer:

Given function:

$f(x)=\sqrt{x}$

Replace f(x) for y:

$\implies y=\sqrt{x}$

Square both sides:

$\implies y^2=x$

This is a sideways parabola that opens to the right, with an axis of symmetry at y = 0.  (Refer to attachment 1)

If we square root this again, we get:

$\implies \sqrt{y^2}=\sqrt{x}$

$\implies y=\pm\sqrt{x}$

So $y=\sqrt{x}$ is the part of the parabola in quadrant I → (x, y)

And $y=-\sqrt{x}$ is the part of the parabola in quadrant IV → (x, -y)

(Refer to attachment 2)

Therefore, the graph of the given function is attachment 3.

Answer 2

The Graph is in the picture above ;)