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worty [1.4K]
1 year ago
12

2/11 into lowest terms

Mathematics
1 answer:
docker41 [41]1 year ago
5 0

If you mean lowest terms as in fully simplified, then your fraction "2/11" is already in lowest terms.
Lowest terms mean that your numerator and denominator have no common factors apart from 1.

2 and 11 don't have any common factors, therefore 2/11 is in lowest terms already.

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an amusement park it's admission price to $15.50 per day, but now charges $1.50 per ride mark has 26 to spend on admission and r
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

26-$15.50=10.5

10.5/1.5=7

he can ride 7 rides in one day

7 0
2 years ago
Convert the equation − x − 2 y = 8 from standard to slope-intercept form
Molodets [167]

Answer:

y = -1/2x - 4

Step-by-step explanation:

We have our equation in standard form: -x - 2y = 8. We can use simplifying rules to isolate y on one side of the equation and give us our y = mx + b format. I'll begin by adding x to both sides.

-x - 2y = 8

-2y = x + 8

Now that we have y on one side, we can divide everything by -2.

-2y/-2 = x/-2 + 8/-2

y = -1/2x - 4

That looks like y = mx + b form.

If you have any further questions or need clarification on anything, let me know!

4 0
2 years ago
I neee some help with 9th grade algebra what is -3x+9x
weeeeeb [17]
It is positive 6x. Hope this helps!
3 0
3 years ago
Read 2 more answers
Need help finding the area
Andreas93 [3]

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5 0
2 years ago
Ross needs to have a procedure done, and since he is over 65 he is on Medicare. Medicare says that according to their plan the a
Anni [7]

Answer:

\large \boxed{\$1200.00}

Step-by-step explanation:

              Let the office charge  = x

     Amount paid by Medicare = ⅞x

Amount paid by Ross = ¼(⅞x) = $262.50

 

Solve for x

\begin{array}{rcrl}\dfrac{1}{4} \left(\dfrac{7}{8}x \right ) & = & \$262.50 & \\\dfrac{7}{32}x & = & \$262.50 & \text{Multiplied the fractions}\\\\7x & = & \$8400.00 & \text{Multiplied each side by 32}\\x & = & \mathbf{\$1200.00} & \text{Divided each side by 7}\\\end{array}\\\text{The office wanted to charge } \large \boxed{\mathbf{\$1200.00}}

Check:

\begin{array}{rcl}\dfrac{1}{4} \left(\dfrac{7}{8}\times \$1200.00 \right ) & = & \$262.50\\\\\dfrac{1}{4} \left(\$1050.00 \right ) & = & \$262.50\\\\\$262.50 & = & \$262.50\\\end{array}

OK.

7 0
2 years ago
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