Answer:
It actually gave you the answer.
Step-by-step explanation:
If you read closer, it's telling you the answer. It's giving you examples of radicals and such.
X² + 8x +y² - 2y -64 =0
We see that the equation has x² and y² . Also we see that coefficients in front of x² and y² are equal. So this is an equation of the circle.
(x² + 8x) +(y² - 2y) -64 =0
(x² + 8x) +(y² - 2y) = 64
We need to complete square for x and y groups, that means it should be written in form (a+b)² or (a-b)².
Expressions in parenthesis we will write as a²+/-2ab+b², to write it after as (a+/-b)², because a²+/-2ab+b² = (a+/-b)²
(x² + 2*4x) +(y² - 2*1y) = 64
(x² + 2*4x+4²) +(y² - 2*1y+1²) = 64+4²+1²
(x+4)² + (y-1)²= 81 Sometimes this is called a standard form of the circle.
(x+4)² + (y-1)²= 9² Sometimes it is required to write like this.
And if you are studying circles,ellipses and hyperbolas, the standard form should look like
We have the following equation:
s = ut + 1 / 2at ^ 2
Clear a for the equation:
1 / 2at ^ 2 = s-ut
at ^ 2 = 2s-2ut
a = 2s / t ^ 2-2ut / t ^ 2
Rewriting:
a = (2s-2ut) / (t ^ 2)
Answer:
An equation that represents a in terms of other variables is:
C. 2s-2ut / t ^ 2
When there is a negative in squre root, it means imaginary number come in. 'i' is usually the varible used to identify imaginary numbers.
First remove the negative from the square root and find the square root of 4, which is 2. Then add i to 2. 2i
Now solve for the positive then negative.
-2 + 2i
----------- = -1 + 1i
2
-2 - 2i
----------- = -1 - 1i
2
Both -1 + 1i and -1 - 1i are the answers.
Answer: x=(6+√196)/4, (6-√196)/4
Step-by-step explanation: