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2 years ago

Find the area (in square feet) of a trapezoid with height h and bases b1 and b2

Mathematics

1 answer:

GalinKa [24]2 years ago

4 0

The area (in square feet) of a trapezoid with height h and bases b1 and b2 is 72 square feet

<h3>Area of a trapezoid</h3>

The formula for calculating the area of the trapezoid is given as:

A = 0.5(b1+b2)h

Given the following

h=12

b1=5

b2=7

Substitute

A = 0.5(5+7)*12
A = 12 * 6

A = 72 square feet

Hence the area (in square feet) of a trapezoid with height h and bases b1 and b2 is 72 square feet

Learn more on area of trapezoid: brainly.com/question/1463152

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Express each decimal as a fraction or mixed number in simplest form.<br><br><br><br> 9-4.

madam [21]

Answer:

Step-by-step explanation:

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3 years ago

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Monica’s lemon cookie recipe calls for 3 cups of sugar. How much much to make 4 1/2 Batches of cookies.

Alex

Answer: 13 & 1/2 cups of sugar

Whole part = 13

Fractional part = 1/2

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Explanation:

4 & 1/2 = 4 + 1/2 = 4 + 0.5 = 4.5

1 batch = 3 cups sugar

4.5*(1 batch) = 4.5*(3 cups sugar)

4.5 batches = 13.5 cups of sugar

The decimal number 13.5 converts to the mixed number 13 & 1/2 which is the same as writing 13 1/2

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2 years ago

2) A girl starts from a point A and walks 285m to B on a bearing of 078°. She then walks due south to a point C which is 307m fr

adelina 88 [10]

Answer:

bearing of A from C is - 65.24°

the distance |BC| is 187.84 m

Step-by-step explanation:

given data

girl walks AB = 285 m (side c)

bearing angle B = 78°

girl walks AC = 307 m (side a)

solution

we use here the Cosine Law for getting side b that is

ac² = ab² + bc² - 2 × ab × cos(B) ...............1

307² = 285² + x² - 2 × 285 cos(78)

x = 187.84 m

and

now we get here angle θ , the bearing from A to C get by law of sines

sin (θ) = $\frac{187.84}{307} \times sin(78)$

sin (θ) = 0.5985

θ = 36.76°

and as we get here angle BAC that is

angle BCA = 180 - ( 36.76° + 78° )

angle BCA = 65.24°

and here negative bearing of A from C so - 65.24°

7 0

3 years ago

Giving Brainliest To the First Correct Answer:)

olga nikolaevna [1]

Answer:

Step-by-step explanation:

12/2=6+4=10

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3 years ago

Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).

Sliva [168]

To compute the distance between the points, we can apply the distance formula as shown below.

$d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }$

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

$\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5$
$\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}$
$\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10$

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

$c^{2} = a^{2} + b^{2} - 2abcosC$

or

$C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})$

Hence, we have

$\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})$
$\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})$
$\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})$

Simplifying this, we have

$\angle AA = 36.03^{0}$
$\angle BB = 126.87^{0}$
$\angle CC = 17.10^{0}$

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB

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3 years ago