What is the slope of the line that passes through the points (-4, 0) and (2, 0) ?
2 answers:
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Answer:
x=4 and y=2
Step-by-step explanation:
Name the triangles as ABC and DEF,
Now, since both the triangles are congruent by HL rule, therefore
(1)
and (2)
Substituting the value of in equation (1), we get
Therefore, Putting y=2 in equation (2),
Answer:
Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank
A . tan(arcsin(x/8))
B . cos (arsin (x/8))
C. (1/2)sin (2arcsin (x/8))
D . sin ( arctan (x/8))
E. cos (arctan (x/8))
These are the spaces to fill out :
.. ..........x/64 (sqrt(64-x^2))
.............x/sqrt(64+x^2)
.............sqrt(64-x^2)/8
..............x/sqrt(64-x^2)
..............8/sqrt(64+x^2)
A. ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)
B . cos (arsin (x/8)) ....sqrt(64-x^2)/8
Step-by-step explanation:
To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus
A we have the sides of the triangle given by x, 8 and or
thus tan(arcsin(x/8)) = =
Therefore ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)
B
Here we have cos = adjacent/hypotenuse where adjacent side is and hypothenuse = 8 we have
/8
B . cos (arsin (x/8)) ....sqrt(64-x^2)/8
