7x-7/79 = 68x+8Find X.
2 answers:
Answer:
x = -639 / 4819 (x = -0.1326 [rounded])
Step-by-step explanation:
7x - 7/79 = 68x + 8
{subtract 7x from both sides to begin to isolate x}
7x - 7/79 = 68x + 8
-7x - 7x
- 7/79 = 61x + 8
{subtract 8 from both sides to isolate x}
- 7/79 = 61x + 8
- 8 -8
{8 = 632/79}
- 639 / 79 = 61x
{divide both sides by 61 to isolate x}
-639 / 79 = 61x
÷ 61 ÷61 ÷
=
*
=
-639 / 4819 = x
(-639/4819 ≈ -0.1326 [rounded] )
{updates in bold}
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Answer:
A.
Statement: ∠6 ≅ ∠14
Reason: For parallel lines cut by a transversal, corresponding angles are congruent.
Step-by-step explanation:
In the figure attached, a plot of the problem is shown.
Given p || q and r is a transversal which cut p and q, then ∠1 ≅ ∠5 and ∠2 ≅ ∠6.
Given r || s and q is a transversal which cut r and s, then ∠6 ≅ ∠14 and ∠8 ≅ ∠16.
From the picture we see that ∠1 and ∠2 are supplementary, that is, their addition is equal to 180º. ∠2 ≅ ∠6 and ∠6 ≅ ∠14, then ∠2 ≅ ∠14, in consequence ∠1 and ∠14 are supplementary.
