Ask question

Ask question

All categories

2 years ago

6

What is the equation of a line that its parallel to -3x+4y=4 and passes through the point (4,0)?

1 answer:

anzhelika [568]2 years ago

7 0

Answer:

y=3/4x-3

Step-by-step explanation:

Okay so to be parallel to an equation of another line, the line must have the same slope but a different y-intercept. First, you need to find the slope of the equation -3x+4y=4. The equation must be in y=mx+b format, so you first move -3x to the right by adding it on both sides, leaving you with 4y=3x+4. Next, you divide 4y by 4 in order to isolate y and do that on the other side. Now, you have y=3/4x+1.

To find the equation of the new line, you must put the point and slope into point slope form: y-y1=m(x-x1). In the point (4, 0), 4 would be x1 and 0 would be y1. so, the new equation is y-0=3/4 (x-4). now, distrubute the 3/4, leaving you with y=3/4x-3. This is correct since the slope remains the same in both equations with a different y-intercept. To check deeper, you could place point (4, 0) on a graph and then rise 3, run 4 until you get the line :) hope this helps

You might be interested in

Help me i dont get this at all

bixtya [17]

Answer:

I think it's the third one.

5 0

2 years ago

Is 0.007x10 equivalent to 0.07

djverab [1.8K]

Answer: yes.

Step-by-step explanation:

adding 10 is moving the decimal point once to the right, so yes.

move the decimal point in 0.007 once to the right (multiply it by 10) and you get 0.07

5 0

2 years ago

Read 2 more answers

Help me please i think its 19

seraphim [82]

I would put d. 117 because 180-63= 117 and go by the opposite interior etc. rules.

6 0

3 years ago

Read 2 more answers

Find the number that is exactly half way between -4 and 10

Katarina [22]

Answer:

3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the <u>first differences</u> between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are <u>not the same</u>, we need to calculate the <u>second differences</u>:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the <u>same</u>, the relationship between the variable is quadratic and will contain an $x^2$ term.

--------------------------------------------------------------------------------------------------

<u>To determine the quadratic equation</u>

The coefficient of $x^2$ is always <u>half</u> of the <u>second difference</u>.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

2 years ago