All categories

2 years ago

Express the statement as an inequality.

Mathematics

1 answer:

Lady_Fox [76]2 years ago

8 0

The expression of the inequality word problems for each question is; As expressed below

<h3>How to express inequalities?</h3>

A) x is negative. This can be expressed as;

x < 0

B) y is non-negative. This can be expressed as;

y > 0

C) q is less than or equal to is expressed as; q ≤

D) d is between 2 and 1 is expressed as 1 < d < 2

E) t is not less than 5 is t ≥ 5

F) The negative of z is not greater than 3 is expressed as;

−z ≤ 3

G) The quotient of p and q is at most 6 is expressed as; p/q ≤ 6

H) The reciprocal of w is at least 9 is 1/w ≥ 9.

Read more about Inequalities at; brainly.com/question/24372553

#SPJ1

You might be interested in

What is the inverse function of f(x)=7x-2

____ [38]

The inverse is f^-1(x) = 2/7 + x/7

7 0

3 years ago

It took the race car 22 minutes to travel 114.4 kilometers. At what rate did the car travel?Use the formula r = d/t, where r is

kramer

D=114.4 kilometers
T=22 minutes

R= 114.4 km /22 min
R= 5.2 km/min

3 0

3 years ago

Read 2 more answers

Jose has scored 562 points on his math tests so far this semester he must score atleast 650 points write and solve an inequality

solniwko [45]

562 + X >= 650
subtract 562 from both sides
X >= 88

5 0

3 years ago

Read 2 more answers

The edges of a cube increase at a rate of 2 cm divided by s. How fast is the volume changing when the length of each edge is 40

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

Let the edge of the cube be a .

Given

$\frac{da}{dt} = 2 cm/s$

Volume V = a³

$\frac{dV}{dt} = 3a^ 2\frac{da}{dt}$

= 3a² x 2

= 6a²

If a = 40 cm

$\frac{dV}{dt} = 6 \times 40\times40$

= 9600 cm³/s .

5 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers