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3 years ago

I need help on 16,17,18,19 please

Mathematics

1 answer:

aev [14]3 years ago

5 0

Answer:

Obtuse stb stb a ad

Step-by-step explanation:

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According to the Food and Drug Administration, the recommended daily intake of irom is 16 mg. This is 4 less than twice the reco

Marrrta [24]

Answer:

Step-by-step explanation:

2z-4=16

2z=20

z=10

10 mg

6 0

3 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

3 years ago

I need help with number 4 someone please help !!

kotykmax [81]

Answer:

50.27 if pi is 3.14

Step-by-step explanation:

6 0

3 years ago

Help with my homework please! Will give brainliest

Anna71 [15]

Answer:

a) 72 cm^2

b) 9 cm^2

c) 9 cm^2

d) 60.39 cm^2

Step-by-step explanation:

a) the the length is 12 cm and the width is 6 cm. Area = lw

A=(12)(6)

A=72 cm^2

b) base equals 3 cm

Height equals 6 cm

A=1/2(3)(6)

A= 9 cm^2

c) base = 3 cm

height=6 cm

Area=1/2(3)(6)

A=9 cm^2

d) to to find the area of the parallelogram, You need to use Pythagorean theorem for one of the triangles.

3^2 + 6^2 = x^2

9 + 36 = x^2

45=x^2

✓45 = ✓x^2

x = 6.71 cm

12-3 = 9

now that you have all the sides for the parallelogram, multiply 6.71 times 9 to get the area.

A= 60.39 cm^2

6 0

3 years ago

Question 3

choli [55]

Answer:

((19)(49)/98)

Step-by-step explanation:

6 0

3 years ago

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